NET JRF PART - A : Questions and Solutions : NET DEC-2013

NET JRF PART - A : Questions and Solutions:

NET DEC-2013

1.) ( 25 ÷ 5 + 3 – 2 × 4 ) + ( 16 × 4 - 3 ) =

(a) 61 (b) 22 (c) 41/24 (d) 16 

Ans. : (a) 61 .

Solution: 

Using BODMAS Rule,

( 25 ÷ 5 + 3 – 2 × 4 ) + ( 16 × 4 - 3 ) = ( 5 + 3 - 8 ) + ( 64 – 3 ) =  0 + 61 = 61 .