NET JRF PART - A : Questions and Solutions : NET JUNE-2014

NET JRF PART - A : Questions and Solutions:

NET JUNE-2014

1.) Find the missing number in the triangle,  

         

                                                                     

(a) 16 (b) 96 (c) 50 (d) 80 

Ans. : (d) 80 .

Solution: 

The number inside the triangle is obtained by the difference of product of numbers of the three vertices and the sum of numbers of the three vertices. 

First triangle: ( 7 × 3 × 5 ) – ( 7 + 3 + 5 ) = 105 – 15 = 90

Second triangle: ( 1 × 6 × 4 ) – ( 1 + 6 + 4 ) = 24 – 11 = 13

Third triangle: ( 8 × 2 × 6 ) – ( 8 + 2 + 6 ) = 96 – 16 = 80

The missing number in the triangle is 80 .